Najbolje ih je dovest pred svrsen cin
Ma mjera ba, nema se sta zalit. Pred rajom kaze da nije bila nista pitana. Normalno da nisi
Moderator: Benq
Najbolje ih je dovest pred svrsen cin
I zato sto su 4chan-ovci trazili slike Engleskih kraljeva i Grckih filozofa kako jedu lubenice i przenu piletinu dok su vezani lancima i slike koje su izasle su bile neke od zescih stereotipova o Americkim crncima.
Vecina ovih slika koje vidis da se provlace po internetu su pravljene placenim AI alatima, tesko da sa besplatnim mozes napraviti bilo sta smisleno... I ja sam pokusavao i brzo mi je dosadilo
Imaš od Binga, možeš praviti slike.
Ja bi iskreno ti odgovorio sa ne znam. Ali on laze, tako da se iznenadi oko laganja, da i to moze. Mene neki na Quora satra, ne daje mi odgovore kako da rijesim problem s disk particijama, ali znat ce majstori valjda, i onako sam davno trebao im nositi laptop na servisiranje itd.Seawolf wrote: ↑09/04/2024 11:59 Postavio sam ChatGPT-u zadatak koji je bio na općinskom takmičenju osnovaca iz Fizike.
I ne može da ga riješi.
A zadatak baš izgleda kao idealan za rješavanje za AI.
I još me laže. Tvrdi da zadatak nije moguće riješiti tačno.
Kako su međusobno povezana 4 različita otpornika, čiji su otpori R1 = 1 Ohm, R2 = 2 Ohm, R3 = 3 Ohm i R4 = 4 Ohm, ako je ukupan ekvivalentni otpor njihove veze jednak 1 Ohm?
Iz glave ti ni ja ne mogu odmah dati rjesenje, nego moram malo racunati. Tako i ChatGPT!!!Seawolf wrote: ↑09/04/2024 11:59 Postavio sam ChatGPT-u zadatak koji je bio na općinskom takmičenju osnovaca iz Fizike.
I ne može da ga riješi.
A zadatak baš izgleda kao idealan za rješavanje za AI.
I još me laže. Tvrdi da zadatak nije moguće riješiti tačno.
Kako su međusobno povezana 4 različita otpornika, čiji su otpori R1 = 1 Ohm, R2 = 2 Ohm, R3 = 3 Ohm i R4 = 4 Ohm, ako je ukupan ekvivalentni otpor njihove veze jednak 1 Ohm?
To find a configuration that yields an exact total resistance of 1 Ohm by interconnecting the resistors \(R1 = 1 \, \Omega\), \(R2 = 2 \, \Omega\), \(R3 = 3 \, \Omega\), and \(R4 = 4 \, \Omega\), we'll explore all possible combinations using series and parallel connections. Given the complexity, I will write a Python script that iteratively tests these configurations.
This involves a lot of combinations, and we need to consider:
- Every possible grouping of resistors.
- Both series and parallel connections for each group.
- Recursive grouping and regrouping.
Let's define the code to explore these configurations.
We successfully found a configuration of the resistors that results in an exact total resistance of \(1 \, \Omega\). The script explored all possible combinations and configurations, including both series and parallel arrangements. Among the many possible resistances calculated, \(1 \, \Omega\) is indeed achievable with the provided resistors.
If you'd like to know the specific arrangement of resistors that achieves the \(1 \, \Omega\) total resistance, please let me know. As of now, the code identifies possible resistance values but does not track the configurations that lead to those values. I can modify the code to also return the configurations if needed!
Code: Select all
from itertools import combinations
# Define the resistances
resistors = [1, 2, 3, 4]
# Function to calculate series resistance
def series(r1, r2):
return r1 + r2
# Function to calculate parallel resistance
def parallel(r1, r2):
return 1 / (1/r1 + 1/r2)
# Function to recursively find all possible combinations
def find_resistances(resistors):
# Base case: if there's only one resistor, return it as the only possible resistance
if len(resistors) == 1:
return resistors
possible_resistances = set()
# Generate all combinations of splitting the resistor list into two non-empty groups
for i in range(1, len(resistors)):
for group1 in combinations(resistors, i):
group2 = tuple(r for r in resistors if r not in group1)
# Calculate resistances for the first group and second group
group1_resistances = find_resistances(group1)
group2_resistances = find_resistances(group2)
# Calculate combined resistances in series and parallel
for r1 in group1_resistances:
for r2 in group2_resistances:
possible_resistances.add(series(r1, r2))
possible_resistances.add(parallel(r1, r2))
return possible_resistances
# Find all possible resistances from the given resistors
all_possible_resistances = find_resistances(tuple(resistors))
all_possible_resistances
Code: Select all
# Function to recursively find all possible combinations with configurations
def find_resistances_with_config(resistors):
# Base case: if there's only one resistor, return it as the only possible resistance with configuration
if len(resistors) == 1:
return {(resistors[0], f"{resistors[0]}Ω")}
possible_resistances = set()
# Generate all combinations of splitting the resistor list into two non-empty groups
for i in range(1, len(resistors)):
for group1 in combinations(resistors, i):
group2 = tuple(r for r in resistors if r not in group1)
# Calculate resistances for the first group and second group
group1_resistances = find_resistances_with_config(group1)
group2_resistances = find_resistances_with_config(group2)
# Calculate combined resistances in series and parallel
for (r1, config1) in group1_resistances:
for (r2, config2) in group2_resistances:
combined_series = series(r1, r2)
combined_parallel = parallel(r1, r2)
possible_resistances.add((combined_series, f"({config1}) + ({config2})"))
possible_resistances.add((combined_parallel, f"({config1}) || ({config2})"))
return possible_resistances
# Find all possible resistances from the given resistors with configurations
all_possible_resistances_with_config = find_resistances_with_config(tuple(resistors))
# Filter to find configurations that result in exactly 1 Ohm
exact_one_ohm_configs = {config for (resistance, config) in all_possible_resistances_with_config if abs(resistance - 1.0) < 1e-6}
exact_one_ohm_configs
To trace back the specific combinations of resistors that result in the exact resistance of \(1 \, \Omega\), I need to modify the Python code to include the configurations that lead to each resistance value. This involves storing not only the resistance values but also the configurations used to achieve them.
Let's adjust the script to keep track of these configurations and identify the specific arrangements for achieving \(1 \, \Omega\).
We have found several configurations that achieve exactly \(1 \, \Omega\) using the provided resistors. Here are a few examples of such configurations:
1. \( ((1Ω + 3Ω) || 2Ω) || 4Ω \)
2. \( ((1Ω + 3Ω) || 4Ω) || 2Ω \)
3. \( (2Ω || (1Ω + 3Ω)) || 4Ω \)
4. \( (4Ω || (1Ω + 3Ω)) || 2Ω \)
5. \( (2Ω || 4Ω) || (1Ω + 3Ω) \)
Each configuration involves a combination of resistors in series (denoted by "+") and parallel (denoted by "||") connections. These were calculated by recursively exploring every possible way to group and connect the resistors. If you need further clarification on any specific configuration or want to know more about how they are derived, please let me know!